Friday, January 25th, 2008
Corrections to assignment 2:
- In question 2, the system S is y(n) = -y(n - 1) - y(n - 2) + x(n)
Corrections to assignment 1 solutions:
-
Output for 1.1:
| n |
-2 |
-1 |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
| x |
0 |
0 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
| y |
0 |
0 |
0 |
1 |
0 |
-1 |
-1 |
0 |
1 |
1 |
0 |
-1 |
-1 |
-
Output for 1.2:
| n |
-2 |
-1 |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
| x |
0 |
0 |
1 |
1 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
| y |
0 |
0 |
0 |
1 |
1 |
0 |
-2 |
-2 |
0 |
2 |
2 |
0 |
-2 |
-
Output for 1.3:
| n |
-2 |
-1 |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
| x |
0 |
0 |
1 |
-1 |
1 |
-1 |
1 |
-1 |
1 |
-1 |
1 |
-1 |
1 |
| y |
0 |
0 |
0 |
1 |
-1 |
0 |
-1 |
1 |
0 |
1 |
-1 |
0 |
-1 |
Alternatively:
| n |
-2 |
-1 |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
| x |
1 |
-1 |
1 |
-1 |
1 |
-1 |
1 |
-1 |
1 |
-1 |
1 |
-1 |
1 |
| y |
0 |
0 |
0 |
2 |
0 |
0 |
-2 |
0 |
0 |
2 |
0 |
0 |
-2 |
-
Matrix A in question 3:
-
Matrix C in question 3: